(1/2x+2)(x^2-12x+36)=0

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Solution for (1/2x+2)(x^2-12x+36)=0 equation: 


x in (-oo:+oo)

((1/2)*x+2)*(x^2-(12*x)+36) = 0

((1/2)*x+2)*(x^2-12*x+36) = 0

(1/2*x+2)*(x^2-12*x+36) = 0

x^2-12*x+36 = 0

x^2-12*x+36 = 0

DELTA = (-12)^2-(1*4*36)

DELTA = 0

x = 12/(1*2)

x = 6 or x = 6

(x-6)^2 = 0

(1/2*x+2)*(x-6)^2 = 0

( 1/2*x+2 )

1/2*x+2 = 0 // - 2

1/2*x = -2 // : 1/2

x = -2/1/2

x = -4

( x-6 )

x-6 = 0 // + 6

x = 6

x in { -4, 6, 6 }

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